What are the solutions to the equation 1800= 1/2 (5)t^2 ?

The solutions to the equation 1800= 1/2 (5)t^2 are t=12sqrt(5),t=-12sqrt(5)

Find the zeros of 1800= 1/2 (5)t^2

The zeros of 1800= 1/2 (5)t^2 are t=12sqrt(5),t=-12sqrt(5)

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1800 = \frac{1}{2} (5) t^{2}

t = 125, t = - 125

Decimal Notation

t = 26.83281 \dots, t = - 26.83281 \dots

Solution steps

1800 = \frac{1}{2} (5) t^{2}

Switch sides

\frac{1}{2} (5) t^{2} = 1800

Simplify

\frac{1}{2} (5) : \frac{5}{2}

\frac{5}{2} t^{2} = 1800

Multiply both sides by

2

5 t^{2} = 3600

Divide both sides by

5

t^{2} = 720

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 720, t = - 720

720 = 125

- 720 = - 125

t = 125, t = - 125

x^{2} - 5 x - 9 = 0

1 + x - 2 x^{2} = 0

- x^{2} + 155 x - 2800 = 0

a^{2} = a + 1

(3 x + 2)^{2}

What are the solutions to the equation 1800= 1/2 (5)t^2 ?
The solutions to the equation 1800= 1/2 (5)t^2 are t=12sqrt(5),t=-12sqrt(5)
Find the zeros of 1800= 1/2 (5)t^2
The zeros of 1800= 1/2 (5)t^2 are t=12sqrt(5),t=-12sqrt(5)