What are the solutions to the equation (4x-1)^2=16 ?

The solutions to the equation (4x-1)^2=16 are x= 5/4 ,x=-3/4

Find the zeros of (4x-1)^2=16

The zeros of (4x-1)^2=16 are x= 5/4 ,x=-3/4

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(4 x - 1)^{2} = 16

x = \frac{5}{4}, x = - \frac{3}{4}

Decimal Notation

x = 1.25, x = - 0.75

Solution steps

(4 x - 1)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 1 = 16 : x = \frac{5}{4}

Solve

4 x - 1 = - 16 : x = - \frac{3}{4}

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = - \frac{3}{4}

- x^{2} + 12 x - 2 = 0

5.5 t^{2} + 44 t - 160 = 0

2 t^{2} + 8 t + 8 = 0

81 (x - 2)^{2} = 16

4 x^{2} - 6 x = 3

What are the solutions to the equation (4x-1)^2=16 ?
The solutions to the equation (4x-1)^2=16 are x= 5/4 ,x=-3/4
Find the zeros of (4x-1)^2=16
The zeros of (4x-1)^2=16 are x= 5/4 ,x=-3/4