What are the solutions to the equation 2(3x-1)^2=32 ?

The solutions to the equation 2(3x-1)^2=32 are x= 5/3 ,x=-1

Find the zeros of 2(3x-1)^2=32

The zeros of 2(3x-1)^2=32 are x= 5/3 ,x=-1

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2 (3 x - 1)^{2} = 32

x = \frac{5}{3}, x = - 1

Decimal Notation

x = 1.66666 \dots, x = - 1

Solution steps

2 (3 x - 1)^{2} = 32

Divide both sides by

2

(3 x - 1)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 1 = 16 : x = \frac{5}{3}

Solve

3 x - 1 = - 16 : x = - 1

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = - 1

16 - x^{2} = 16 - 8 x + x^{2}

(x + 1)^{2} - 9 (x + 1) + 20 = 0

m^{2} - 42 m + 6 = 0

12 - 4 x - x^{2} = 0

x, x^{2} + y^{2} - 6 x + 9 = 0

What are the solutions to the equation 2(3x-1)^2=32 ?
The solutions to the equation 2(3x-1)^2=32 are x= 5/3 ,x=-1
Find the zeros of 2(3x-1)^2=32
The zeros of 2(3x-1)^2=32 are x= 5/3 ,x=-1