What are the solutions to the equation solvefor y,x=2y^2 ?

The solutions to the equation solvefor y,x=2y^2 are y=sqrt(x/2),y=-sqrt(x/2)

Find the zeros of solvefor y,x=2y^2

The zeros of solvefor y,x=2y^2 are y=sqrt(x/2),y=-sqrt(x/2)

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solve for

y, x = 2 y^{2}

y = \frac{x}{2}, y = - \frac{x}{2}

Solution steps

x = 2 y^{2}

Switch sides

2 y^{2} = x

Divide both sides by

2

y^{2} = \frac{x}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{x}{2}, y = - \frac{x}{2}

x^{2} + 4 x - 32

x^{2} - 3 x - 5 = 0

9 x^{2} - 24 x - 24 = 0

14 x + 3 = - 8 x^{2}

2 x^{2} - 12 = 2 x

What are the solutions to the equation solvefor y,x=2y^2 ?
The solutions to the equation solvefor y,x=2y^2 are y=sqrt(x/2),y=-sqrt(x/2)
Find the zeros of solvefor y,x=2y^2
The zeros of solvefor y,x=2y^2 are y=sqrt(x/2),y=-sqrt(x/2)