What are the solutions to the equation (3x-5)^2=19 ?

The solutions to the equation (3x-5)^2=19 are x=(sqrt(19)+5)/3 ,x=(-sqrt(19)+5)/3

Find the zeros of (3x-5)^2=19

The zeros of (3x-5)^2=19 are x=(sqrt(19)+5)/3 ,x=(-sqrt(19)+5)/3

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(3 x - 5)^{2} = 19

x = \frac{19 + 5}{3}, x = \frac{- 19 + 5}{3}

Decimal Notation

x = 3.11963 \dots, x = 0.21370 \dots

Solution steps

(3 x - 5)^{2} = 19

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 5 = 19 : x = \frac{19 + 5}{3}

Solve

3 x - 5 = - 19 : x = \frac{- 19 + 5}{3}

The solutions to the quadratic equation are:

x = \frac{19 + 5}{3}, x = \frac{- 19 + 5}{3}

\frac{x ^{2}}{3 y} + 4 y

\frac{3}{8} \cdot \frac{1}{3}

7 < 4 q - 9

9 n^{2} + 24 n + 16

\frac{1}{4} 8

What are the solutions to the equation (3x-5)^2=19 ?
The solutions to the equation (3x-5)^2=19 are x=(sqrt(19)+5)/3 ,x=(-sqrt(19)+5)/3
Find the zeros of (3x-5)^2=19
The zeros of (3x-5)^2=19 are x=(sqrt(19)+5)/3 ,x=(-sqrt(19)+5)/3