What are the solutions to the equation 4(x+5)^2=-64 ?

The solutions to the equation 4(x+5)^2=-64 are x=4i-5,x=-4i-5

Find the zeros of 4(x+5)^2=-64

The zeros of 4(x+5)^2=-64 are x=4i-5,x=-4i-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 (x + 5)^{2} = - 64

x = 4 i - 5, x = - 4 i - 5

Solution steps

4 (x + 5)^{2} = - 64

Divide both sides by

4

(x + 5)^{2} = - 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = - 16 : x = 4 i - 5

Solve

x + 5 = - - 16 : x = - 4 i - 5

The solutions to the quadratic equation are:

x = 4 i - 5, x = - 4 i - 5

2 x^{2} + 4 x + 18 = 0

5^{2} + b^{2} = 1 2^{2}

x^{2} + 3 x - 6 = 8

d^{2} + d - 72 = 0

x^{2} - x + 56 = 0

What are the solutions to the equation 4(x+5)^2=-64 ?
The solutions to the equation 4(x+5)^2=-64 are x=4i-5,x=-4i-5
Find the zeros of 4(x+5)^2=-64
The zeros of 4(x+5)^2=-64 are x=4i-5,x=-4i-5