What are the solutions to the equation (x+1/2)(x-2)=0 ?

The solutions to the equation (x+1/2)(x-2)=0 are x=-1/2 ,x=2

Find the zeros of (x+1/2)(x-2)=0

The zeros of (x+1/2)(x-2)=0 are x=-1/2 ,x=2

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(x + \frac{1}{2}) (x - 2) = 0

x = - \frac{1}{2}, x = 2

Decimal Notation

x = - 0.5, x = 2

Solution steps

(x + \frac{1}{2}) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + \frac{1}{2} = 0 or x - 2 = 0

Solve

x + \frac{1}{2} = 0 : x = - \frac{1}{2}

Solve

x - 2 = 0 : x = 2

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = 2

4 x^{2} + 6 = 25 x

x^{2} + 8 x - 2 = 0

x^{2} + 7 x + 6 = 0

30 - 13 x - 15 x^{2} = 0

y = x^{2} - 7 x + 12, x

What are the solutions to the equation (x+1/2)(x-2)=0 ?
The solutions to the equation (x+1/2)(x-2)=0 are x=-1/2 ,x=2
Find the zeros of (x+1/2)(x-2)=0
The zeros of (x+1/2)(x-2)=0 are x=-1/2 ,x=2