What are the solutions to the equation 2x^2+20x=6 ?

The solutions to the equation 2x^2+20x=6 are x=-5+2sqrt(7),x=-5-2sqrt(7)

Find the zeros of 2x^2+20x=6

The zeros of 2x^2+20x=6 are x=-5+2sqrt(7),x=-5-2sqrt(7)

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2 x^{2} + 20 x = 6

x = - 5 + 27, x = - 5 - 27

Decimal Notation

x = 0.29150 \dots, x = - 10.29150 \dots

Solution steps

2 x^{2} + 20 x = 6

Move

6

to the left side

2 x^{2} + 20 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

2 0^{2} - 4 \cdot 2 (- 6) = 87

x_{1, 2} = \frac{- 20 \pm 8 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 20 + 8 7}{2 \cdot 2}, x_{2} = \frac{- 20 - 8 7}{2 \cdot 2}

x = \frac{- 20 + 8 7}{2 \cdot 2} : - 5 + 27

x = \frac{- 20 - 8 7}{2 \cdot 2} : - 5 - 27

The solutions to the quadratic equation are:

x = - 5 + 27, x = - 5 - 27

x^{2} + 0.7 x - 2.6 = 0

(5 h + 4)^{2} = 16

(3 x + 13) (x + 16) = 0

(2 - x)^{2} = 9

76 x^{2} - 72 = 9 - 24 x^{2}

What are the solutions to the equation 2x^2+20x=6 ?
The solutions to the equation 2x^2+20x=6 are x=-5+2sqrt(7),x=-5-2sqrt(7)
Find the zeros of 2x^2+20x=6
The zeros of 2x^2+20x=6 are x=-5+2sqrt(7),x=-5-2sqrt(7)