What are the solutions to the equation 2(x-5)^2-64=0 ?

The solutions to the equation 2(x-5)^2-64=0 are x=4sqrt(2)+5,x=-4sqrt(2)+5

Find the zeros of 2(x-5)^2-64=0

The zeros of 2(x-5)^2-64=0 are x=4sqrt(2)+5,x=-4sqrt(2)+5

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2 (x - 5)^{2} - 64 = 0

x = 42 + 5, x = - 42 + 5

Decimal Notation

x = 10.65685 \dots, x = - 0.65685 \dots

Solution steps

2 (x - 5)^{2} - 64 = 0

Move

64

to the right side

2 (x - 5)^{2} = 64

Divide both sides by

2

(x - 5)^{2} = 32

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = 32 : x = 42 + 5

Solve

x - 5 = - 32 : x = - 42 + 5

The solutions to the quadratic equation are:

x = 42 + 5, x = - 42 + 5

s, A = s^{2}

x^{2} + 6 x + 2 = 0

(d + 1) (d - 5) = 2 d^{2} - 7

4 = 3 t^{2} - t

k^{2} + 15 k = - 56

What are the solutions to the equation 2(x-5)^2-64=0 ?
The solutions to the equation 2(x-5)^2-64=0 are x=4sqrt(2)+5,x=-4sqrt(2)+5
Find the zeros of 2(x-5)^2-64=0
The zeros of 2(x-5)^2-64=0 are x=4sqrt(2)+5,x=-4sqrt(2)+5