What are the solutions to the equation solvefor x,x(x+5)=-6 ?

The solutions to the equation solvefor x,x(x+5)=-6 are x=-2,x=-3

Find the zeros of solvefor x,x(x+5)=-6

The zeros of solvefor x,x(x+5)=-6 are x=-2,x=-3

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x, x (x + 5) = - 6

x = - 2, x = - 3

Solution steps

x (x + 5) = - 6

Expand

x (x + 5) : x^{2} + 5 x

x^{2} + 5 x = - 6

Move

6

to the left side

x^{2} + 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

x_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 1}{2 \cdot 1}, x_{2} = \frac{- 5 - 1}{2 \cdot 1}

x = \frac{- 5 + 1}{2 \cdot 1} : - 2

x = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = - 2, x = - 3

x^{2} - 2 x = \frac{5}{2}

x, 5 x^{2} + 10 x + 4 = 0

(5 x - 4)^{2} = - 32

a^{2} - 10 a + 9 = 0

4 - 2 x^{2} = 3

What are the solutions to the equation solvefor x,x(x+5)=-6 ?
The solutions to the equation solvefor x,x(x+5)=-6 are x=-2,x=-3
Find the zeros of solvefor x,x(x+5)=-6
The zeros of solvefor x,x(x+5)=-6 are x=-2,x=-3