What are the solutions to the equation (11x-12)^2=20 ?

The solutions to the equation (11x-12)^2=20 are x=(2sqrt(5)+12)/(11),x=(-2sqrt(5)+12)/(11)

Find the zeros of (11x-12)^2=20

The zeros of (11x-12)^2=20 are x=(2sqrt(5)+12)/(11),x=(-2sqrt(5)+12)/(11)

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(11 x - 12)^{2} = 20

x = \frac{2 5 + 12}{11}, x = \frac{- 2 5 + 12}{11}

Decimal Notation

x = 1.49746 \dots, x = 0.68435 \dots

Solution steps

(11 x - 12)^{2} = 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

11 x - 12 = 20 : x = \frac{2 5 + 12}{11}

Solve

11 x - 12 = - 20 : x = \frac{- 2 5 + 12}{11}

The solutions to the quadratic equation are:

x = \frac{2 5 + 12}{11}, x = \frac{- 2 5 + 12}{11}

8 - (x + 4)^{2} = 4 - (0.5 x + 1.8)^{2}

(2 x) x - 1 = 4

9 x^{2} + 18 x + 14 = 0

3 a^{2} - 10 a = 8

- x^{2} + 4 x = 3

What are the solutions to the equation (11x-12)^2=20 ?
The solutions to the equation (11x-12)^2=20 are x=(2sqrt(5)+12)/(11),x=(-2sqrt(5)+12)/(11)
Find the zeros of (11x-12)^2=20
The zeros of (11x-12)^2=20 are x=(2sqrt(5)+12)/(11),x=(-2sqrt(5)+12)/(11)