What are the solutions to the equation 64x^2+16x+1=28 ?

The solutions to the equation 64x^2+16x+1=28 are x=(-1+2sqrt(7))/8 ,x=-(1+2sqrt(7))/8

Find the zeros of 64x^2+16x+1=28

The zeros of 64x^2+16x+1=28 are x=(-1+2sqrt(7))/8 ,x=-(1+2sqrt(7))/8

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64 x^{2} + 16 x + 1 = 28

x = \frac{- 1 + 2 7}{8}, x = - \frac{1 + 2 7}{8}

Decimal Notation

x = 0.53643 \dots, x = - 0.78643 \dots

Solution steps

64 x^{2} + 16 x + 1 = 28

Move

28

to the left side

64 x^{2} + 16 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 64 ( - 27 )}{2 \cdot 64}

1 6^{2} - 4 \cdot 64 (- 27) = 327

x_{1, 2} = \frac{- 16 \pm 32 7}{2 \cdot 64}

Separate the solutions

x_{1} = \frac{- 16 + 32 7}{2 \cdot 64}, x_{2} = \frac{- 16 - 32 7}{2 \cdot 64}

x = \frac{- 16 + 32 7}{2 \cdot 64} : \frac{- 1 + 2 7}{8}

x = \frac{- 16 - 32 7}{2 \cdot 64} : - \frac{1 + 2 7}{8}

The solutions to the quadratic equation are:

x = \frac{- 1 + 2 7}{8}, x = - \frac{1 + 2 7}{8}

10 x^{2} + 21.21 x - 45 = 0

- 2 x^{2} = 5 x - 3

4 x^{2} - 18 = - 9

- 5 x^{2} + 24.5 x = 0

2 x (x + 2) = 1

What are the solutions to the equation 64x^2+16x+1=28 ?
The solutions to the equation 64x^2+16x+1=28 are x=(-1+2sqrt(7))/8 ,x=-(1+2sqrt(7))/8
Find the zeros of 64x^2+16x+1=28
The zeros of 64x^2+16x+1=28 are x=(-1+2sqrt(7))/8 ,x=-(1+2sqrt(7))/8