What are the solutions to the equation (x+3)(x-2)=6 ?

The solutions to the equation (x+3)(x-2)=6 are x=3,x=-4

Find the zeros of (x+3)(x-2)=6

The zeros of (x+3)(x-2)=6 are x=3,x=-4

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(x + 3) (x - 2) = 6

x = 3, x = - 4

Solution steps

(x + 3) (x - 2) = 6

Expand

(x + 3) (x - 2) : x^{2} + x - 6

x^{2} + x - 6 = 6

Move

6

to the left side

x^{2} + x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 12) = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 7}{2 \cdot 1}, x_{2} = \frac{- 1 - 7}{2 \cdot 1}

x = \frac{- 1 + 7}{2 \cdot 1} : 3

x = \frac{- 1 - 7}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 3, x = - 4

- 5 x^{2} - 90 x - 765 = 0

2 x - 3 x^{2} = 5

3 v^{2} + 18 v = 0

2 x^{2} - 21 x + 49 = 0

3 x^{2} + x = 400

What are the solutions to the equation (x+3)(x-2)=6 ?
The solutions to the equation (x+3)(x-2)=6 are x=3,x=-4
Find the zeros of (x+3)(x-2)=6
The zeros of (x+3)(x-2)=6 are x=3,x=-4