What are the solutions to the equation 10x+18+2x^2+2=4x^2+28 ?

The solutions to the equation 10x+18+2x^2+2=4x^2+28 are x=1,x=4

Find the zeros of 10x+18+2x^2+2=4x^2+28

The zeros of 10x+18+2x^2+2=4x^2+28 are x=1,x=4

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10 x + 18 + 2 x^{2} + 2 = 4 x^{2} + 28

x = 1, x = 4

Solution steps

10 x + 18 + 2 x^{2} + 2 = 4 x^{2} + 28

Refine

2 x^{2} + 10 x + 20 = 4 x^{2} + 28

Move

28

to the left side

2 x^{2} + 10 x - 8 = 4 x^{2}

Move

4 x^{2}

to the left side

- 2 x^{2} + 10 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 2 ) ( - 8 )}{2 ( - 2 )}

1 0^{2} - 4 (- 2) (- 8) = 6

x_{1, 2} = \frac{- 10 \pm 6}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 10 + 6}{2 ( - 2 )}, x_{2} = \frac{- 10 - 6}{2 ( - 2 )}

x = \frac{- 10 + 6}{2 ( - 2 )} : 1

x = \frac{- 10 - 6}{2 ( - 2 )} : 4

The solutions to the quadratic equation are:

x = 1, x = 4

y^{2} - 5 = 0

64 = 80 x - 16 x^{2}

(x + 2) (x - 6) + 101 = (2 x - 5) (x + 3)

(x - 3)^{2} + 8 = 17

4 y^{2} - 225 = 0

What are the solutions to the equation 10x+18+2x^2+2=4x^2+28 ?
The solutions to the equation 10x+18+2x^2+2=4x^2+28 are x=1,x=4
Find the zeros of 10x+18+2x^2+2=4x^2+28
The zeros of 10x+18+2x^2+2=4x^2+28 are x=1,x=4