What are the solutions to the equation 20-3y^2=11y ?

The solutions to the equation 20-3y^2=11y are y=-5,y= 4/3

Find the zeros of 20-3y^2=11y

The zeros of 20-3y^2=11y are y=-5,y= 4/3

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20 - 3 y^{2} = 11 y

y = - 5, y = \frac{4}{3}

Decimal Notation

y = - 5, y = 1.33333 \dots

Solution steps

20 - 3 y^{2} = 11 y

Move

11 y

to the left side

20 - 3 y^{2} - 11 y = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 y^{2} - 11 y + 20 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 ( - 3 ) \cdot 20}{2 ( - 3 )}

(- 11)^{2} - 4 (- 3) \cdot 20 = 19

y_{1, 2} = \frac{- ( - 11 ) \pm 19}{2 ( - 3 )}

Separate the solutions

y_{1} = \frac{- ( - 11 ) + 19}{2 ( - 3 )}, y_{2} = \frac{- ( - 11 ) - 19}{2 ( - 3 )}

y = \frac{- ( - 11 ) + 19}{2 ( - 3 )} : - 5

y = \frac{- ( - 11 ) - 19}{2 ( - 3 )} : \frac{4}{3}

The solutions to the quadratic equation are:

y = - 5, y = \frac{4}{3}

- 8 \leq 3 x + 6 \leq \frac{1}{2}

3 y^{2} + 12 = 0

x^{2} - 61 = 20

\frac{4 ( c ) ^{3}}{3 c ^{7}}

2 (4 x - 6) = 6 x - 4

What are the solutions to the equation 20-3y^2=11y ?
The solutions to the equation 20-3y^2=11y are y=-5,y= 4/3
Find the zeros of 20-3y^2=11y
The zeros of 20-3y^2=11y are y=-5,y= 4/3