What are the solutions to the equation x^2=8^2+2^2 ?

The solutions to the equation x^2=8^2+2^2 are x=2sqrt(17),x=-2sqrt(17)

Find the zeros of x^2=8^2+2^2

The zeros of x^2=8^2+2^2 are x=2sqrt(17),x=-2sqrt(17)

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x^{2} = 8^{2} + 2^{2}

x = 217, x = - 217

Decimal

x = 8.24621 \dots, x = - 8.24621 \dots

Solution steps

x^{2} = 8^{2} + 2^{2}

Simplify

8^{2} + 2^{2} : 68

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 68, x = - 68

68 = 217

- 68 = - 217

x = 217, x = - 217

2 x^{2} = 5 x + 42

3 y^{2} + 8 y - 3 = 0

x^{2} - x + 1 = 0

x - x^{2} = - x - 7

x^{2} - 40 = - 6 x

What are the solutions to the equation x^2=8^2+2^2 ?
The solutions to the equation x^2=8^2+2^2 are x=2sqrt(17),x=-2sqrt(17)
Find the zeros of x^2=8^2+2^2
The zeros of x^2=8^2+2^2 are x=2sqrt(17),x=-2sqrt(17)