What are the solutions to the equation y^2-12=4 ?

The solutions to the equation y^2-12=4 are y=4,y=-4

Find the zeros of y^2-12=4

The zeros of y^2-12=4 are y=4,y=-4

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y^{2} - 12 = 4

y = 4, y = - 4

Solution steps

y^{2} - 12 = 4

Move

12

to the right side

y^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 16, y = - 16

16 = 4

- 16 = - 4

y = 4, y = - 4

- 3 x^{2} + x + 3 = 0

2 x^{2} + 5 = \frac{418}{16}

10 (p^{2} - 1) = 21 p

- 16 t^{2} + 70 t + 1 = 41

3 x^{2} + 14 - 5 = 0

What are the solutions to the equation y^2-12=4 ?
The solutions to the equation y^2-12=4 are y=4,y=-4
Find the zeros of y^2-12=4
The zeros of y^2-12=4 are y=4,y=-4