What are the solutions to the equation x^2+5x-3=-3 ?

The solutions to the equation x^2+5x-3=-3 are x=0,x=-5

Find the zeros of x^2+5x-3=-3

The zeros of x^2+5x-3=-3 are x=0,x=-5

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x^{2} + 5 x - 3 = - 3

x = 0, x = - 5

Solution steps

x^{2} + 5 x - 3 = - 3

Move

3

to the left side

x^{2} + 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 0 = 5

x_{1, 2} = \frac{- 5 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 5}{2 \cdot 1}, x_{2} = \frac{- 5 - 5}{2 \cdot 1}

x = \frac{- 5 + 5}{2 \cdot 1} : 0

x = \frac{- 5 - 5}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 0, x = - 5

7 c^{2} = c + 6

x^{2} + x - 20 = 0

p^{2} + 4 p = 0

b^{2} = - 36

x, x^{2} y - x^{2} - 8 y = 0

What are the solutions to the equation x^2+5x-3=-3 ?
The solutions to the equation x^2+5x-3=-3 are x=0,x=-5
Find the zeros of x^2+5x-3=-3
The zeros of x^2+5x-3=-3 are x=0,x=-5