What are the solutions to the equation (y+1)^2=9 ?

The solutions to the equation (y+1)^2=9 are y=2,y=-4

Find the zeros of (y+1)^2=9

The zeros of (y+1)^2=9 are y=2,y=-4

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(y + 1)^{2} = 9

y = 2, y = - 4

Solution steps

(y + 1)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y + 1 = 9 : y = 2

Solve

y + 1 = - 9 : y = - 4

The solutions to the quadratic equation are:

y = 2, y = - 4

x, 36 x^{2} = - 60 x - 25

2 y (4 y - 3) - 5 = 0

2 x - 7 = 4 x^{2}

x, x^{2} - 4 x - 2 = 0

0 = 2 x^{2} - x

What are the solutions to the equation (y+1)^2=9 ?
The solutions to the equation (y+1)^2=9 are y=2,y=-4
Find the zeros of (y+1)^2=9
The zeros of (y+1)^2=9 are y=2,y=-4