What are the solutions to the equation (s^2+8s+272)=0 ?

The solutions to the equation (s^2+8s+272)=0 are s=-4+16i,s=-4-16i

Find the zeros of (s^2+8s+272)=0

The zeros of (s^2+8s+272)=0 are s=-4+16i,s=-4-16i

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(s^{2} + 8 s + 272) = 0

s = - 4 + 16 i, s = - 4 - 16 i

Solution steps

(s^{2} + 8 s + 272) = 0

Refine

s^{2} + 8 s + 272 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 272}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 272 : 32 i

s_{1, 2} = \frac{- 8 \pm 32 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 8 + 32 i}{2 \cdot 1}, s_{2} = \frac{- 8 - 32 i}{2 \cdot 1}

s = \frac{- 8 + 32 i}{2 \cdot 1} : - 4 + 16 i

s = \frac{- 8 - 32 i}{2 \cdot 1} : - 4 - 16 i

The solutions to the quadratic equation are:

s = - 4 + 16 i, s = - 4 - 16 i

(x - 4)^{2} = - 36

11 x^{2} + 16 x - 21 = 0

- 4 x^{2} = 12 x

\frac{1}{2} x^{2} = \frac{1}{4}

3 x^{2} - 15 x + 6 = 0

What are the solutions to the equation (s^2+8s+272)=0 ?
The solutions to the equation (s^2+8s+272)=0 are s=-4+16i,s=-4-16i
Find the zeros of (s^2+8s+272)=0
The zeros of (s^2+8s+272)=0 are s=-4+16i,s=-4-16i