What are the solutions to the equation x(x-6)+8=0 ?

The solutions to the equation x(x-6)+8=0 are x=4,x=2

Find the zeros of x(x-6)+8=0

The zeros of x(x-6)+8=0 are x=4,x=2

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x (x - 6) + 8 = 0

x = 4, x = 2

Solution steps

x (x - 6) + 8 = 0

Expand

x (x - 6) + 8 : x^{2} - 6 x + 8

x^{2} - 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 8 = 2

x_{1, 2} = \frac{- ( - 6 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2}{2 \cdot 1} : 4

x = \frac{- ( - 6 ) - 2}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 4, x = 2

w^{2} + 7 w + 6 = 0

a, (a + b)^{2} = 64

(4 k - 4)^{2} - 4 (2 k + 1) (- k) = 0

x, f = 2 x^{2} - 3 f (a + 1)

- 4 b = - 3 b^{2} + 15

What are the solutions to the equation x(x-6)+8=0 ?
The solutions to the equation x(x-6)+8=0 are x=4,x=2
Find the zeros of x(x-6)+8=0
The zeros of x(x-6)+8=0 are x=4,x=2