What are the solutions to the equation -4=(x-3)^2-4 ?

The solutions to the equation -4=(x-3)^2-4 are x=3

Find the zeros of -4=(x-3)^2-4

The zeros of -4=(x-3)^2-4 are x=3

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- 4 = (x - 3)^{2} - 4

x = 3

Solution steps

- 4 = (x - 3)^{2} - 4

Switch sides

(x - 3)^{2} - 4 = - 4

Move

4

to the right side

(x - 3)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x - 3 = 0 : x = 3

The solution to the quadratic equation is:

x = 3

2 x^{2} - 6 = - 206

(x + 1) (x - 2) = 3 (x - 2)

2 x^{2} - x - 20 = 0

x^{2} + b x = c

49 = 100 y^{2}

What are the solutions to the equation -4=(x-3)^2-4 ?
The solutions to the equation -4=(x-3)^2-4 are x=3
Find the zeros of -4=(x-3)^2-4
The zeros of -4=(x-3)^2-4 are x=3