What are the solutions to the equation 4x^2+16x+8=0 ?

The solutions to the equation 4x^2+16x+8=0 are x=-2+sqrt(2),x=-2-sqrt(2)

Find the zeros of 4x^2+16x+8=0

The zeros of 4x^2+16x+8=0 are x=-2+sqrt(2),x=-2-sqrt(2)

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4 x^{2} + 16 x + 8 = 0

x = - 2 + 2, x = - 2 - 2

Decimal Notation

x = - 0.58578 \dots, x = - 3.41421 \dots

Solution steps

4 x^{2} + 16 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 4 \cdot 8}{2 \cdot 4}

1 6^{2} - 4 \cdot 4 \cdot 8 = 82

x_{1, 2} = \frac{- 16 \pm 8 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 16 + 8 2}{2 \cdot 4}, x_{2} = \frac{- 16 - 8 2}{2 \cdot 4}

x = \frac{- 16 + 8 2}{2 \cdot 4} : - 2 + 2

x = \frac{- 16 - 8 2}{2 \cdot 4} : - 2 - 2

The solutions to the quadratic equation are:

x = - 2 + 2, x = - 2 - 2

2 x (x + 3) = 1

2 x (x + 3) = 3

2 x (x + 3) = 2

(- x - 2) = x^{2} + 4

x^{2} + 4 x + 53 = 15

What are the solutions to the equation 4x^2+16x+8=0 ?
The solutions to the equation 4x^2+16x+8=0 are x=-2+sqrt(2),x=-2-sqrt(2)
Find the zeros of 4x^2+16x+8=0
The zeros of 4x^2+16x+8=0 are x=-2+sqrt(2),x=-2-sqrt(2)