What are the solutions to the equation 18x^2-7x=1 ?

The solutions to the equation 18x^2-7x=1 are x= 1/2 ,x=-1/9

Find the zeros of 18x^2-7x=1

The zeros of 18x^2-7x=1 are x= 1/2 ,x=-1/9

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18 x^{2} - 7 x = 1

x = \frac{1}{2}, x = - \frac{1}{9}

Decimal Notation

x = 0.5, x = - 0.11111 \dots

Solution steps

18 x^{2} - 7 x = 1

Move

1

to the left side

18 x^{2} - 7 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 18 ( - 1 )}{2 \cdot 18}

(- 7)^{2} - 4 \cdot 18 (- 1) = 11

x_{1, 2} = \frac{- ( - 7 ) \pm 11}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 11}{2 \cdot 18}, x_{2} = \frac{- ( - 7 ) - 11}{2 \cdot 18}

x = \frac{- ( - 7 ) + 11}{2 \cdot 18} : \frac{1}{2}

x = \frac{- ( - 7 ) - 11}{2 \cdot 18} : - \frac{1}{9}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{1}{9}

y^{2} - 4 y = 5

x^{2} - 18 (x - 4) = 0

3 a^{2} - 8 a + 4 = 0

x^{2} + 2 x + 5 = - 5

x, f (x + 1) = 2 x^{2} + x - 1

What are the solutions to the equation 18x^2-7x=1 ?
The solutions to the equation 18x^2-7x=1 are x= 1/2 ,x=-1/9
Find the zeros of 18x^2-7x=1
The zeros of 18x^2-7x=1 are x= 1/2 ,x=-1/9