What are the solutions to the equation completesquare x^2+6x-12=0 ?

The solutions to the equation completesquare x^2+6x-12=0 are x=sqrt(21)-3,x=-sqrt(21)-3

Find the zeros of completesquare x^2+6x-12=0

The zeros of completesquare x^2+6x-12=0 are x=sqrt(21)-3,x=-sqrt(21)-3

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x^{2} + 6 x - 12 = 0

x = 21 - 3, x = - 21 - 3

Decimal Notation

x = 1.58257 \dots, x = - 7.58257 \dots

Solution steps

x^{2} + 6 x - 12 = 0

Move

12

to the right side

x^{2} + 6 x = 12

Rewrite in the form

(x + a)^{2} = b

(x + 3)^{2} = 21

For

the solutions are

f (x) = a, - a

Solve

x + 3 = 21 : x = 21 - 3

Solve

x + 3 = - 21 : x = - 21 - 3

The solutions to the quadratic equation are:

x = 21 - 3, x = - 21 - 3

(x - \frac{3}{2})^{2} = 0

x^{2} - 4 x + 8 = 13

4 a^{2} + 432 = 0

m (x) = 3 x^{2} + x - 5 m (\frac{1}{2})

x^{2} + 4 x + 4 = x^{2} + x^{2} + 2 x + 1

What are the solutions to the equation completesquare x^2+6x-12=0 ?
The solutions to the equation completesquare x^2+6x-12=0 are x=sqrt(21)-3,x=-sqrt(21)-3
Find the zeros of completesquare x^2+6x-12=0
The zeros of completesquare x^2+6x-12=0 are x=sqrt(21)-3,x=-sqrt(21)-3