What are the solutions to the equation 7p^2+10=26 ?

The solutions to the equation 7p^2+10=26 are p= 4/(sqrt(7)),p=-4/(sqrt(7))

Find the zeros of 7p^2+10=26

The zeros of 7p^2+10=26 are p= 4/(sqrt(7)),p=-4/(sqrt(7))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7 p^{2} + 10 = 26

p = \frac{4}{7}, p = - \frac{4}{7}

Decimal Notation

p = 1.51185 \dots, p = - 1.51185 \dots

Solution steps

7 p^{2} + 10 = 26

Move

10

to the right side

7 p^{2} = 16

Divide both sides by

7

p^{2} = \frac{16}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = \frac{16}{7}, p = - \frac{16}{7}

\frac{16}{7} = \frac{4}{7}

- \frac{16}{7} = - \frac{4}{7}

p = \frac{4}{7}, p = - \frac{4}{7}

9 v^{2} + 4 = 571

6 t - 3 t^{2} = 0

x, 2 x^{2} = y (25 - x^{2})

t^{2} = 2 t

16 x^{2} - x = 0

What are the solutions to the equation 7p^2+10=26 ?
The solutions to the equation 7p^2+10=26 are p= 4/(sqrt(7)),p=-4/(sqrt(7))
Find the zeros of 7p^2+10=26
The zeros of 7p^2+10=26 are p= 4/(sqrt(7)),p=-4/(sqrt(7))