What are the solutions to the equation quadraticformula 4x^2+8x+3=0 ?

The solutions to the equation quadraticformula 4x^2+8x+3=0 are x=-1/2 ,x=-3/2

Find the zeros of quadraticformula 4x^2+8x+3=0

The zeros of quadraticformula 4x^2+8x+3=0 are x=-1/2 ,x=-3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 8 x + 3 = 0

x = - \frac{1}{2}, x = - \frac{3}{2}

Decimal Notation

x = - 0.5, x = - 1.5

Solution steps

4 x^{2} + 8 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

8^{2} - 4 \cdot 4 \cdot 3 = 4

x_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 4}{2 \cdot 4}, x_{2} = \frac{- 8 - 4}{2 \cdot 4}

x = \frac{- 8 + 4}{2 \cdot 4} : - \frac{1}{2}

x = \frac{- 8 - 4}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - \frac{3}{2}

5 x^{2} - 18 = 0

4 x^{2} - 20 x + 100 = 0

8 x^{2} - 6 x - 2 = 0

X^{2} + X - 30 = 0

2 (x^{2} + 2) = 22

What are the solutions to the equation quadraticformula 4x^2+8x+3=0 ?
The solutions to the equation quadraticformula 4x^2+8x+3=0 are x=-1/2 ,x=-3/2
Find the zeros of quadraticformula 4x^2+8x+3=0
The zeros of quadraticformula 4x^2+8x+3=0 are x=-1/2 ,x=-3/2