What are the solutions to the equation 6-2x^2=1 ?

The solutions to the equation 6-2x^2=1 are x=sqrt(5/2),x=-sqrt(5/2)

Find the zeros of 6-2x^2=1

The zeros of 6-2x^2=1 are x=sqrt(5/2),x=-sqrt(5/2)

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6 - 2 x^{2} = 1

x = \frac{5}{2}, x = - \frac{5}{2}

Decimal Notation

x = 1.58113 \dots, x = - 1.58113 \dots

Solution steps

6 - 2 x^{2} = 1

Move

6

to the right side

- 2 x^{2} = - 5

Divide both sides by

- 2

x^{2} = \frac{5}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{5}{2}, x = - \frac{5}{2}

v^{2} + 3 v - 10 = 0

2 p^{2} - 3 p + 1 = 0

x^{2} - 2 x + 3 = \frac{x}{2} + 2

5 x = x^{2} + 6

u^{2} = 24

What are the solutions to the equation 6-2x^2=1 ?
The solutions to the equation 6-2x^2=1 are x=sqrt(5/2),x=-sqrt(5/2)
Find the zeros of 6-2x^2=1
The zeros of 6-2x^2=1 are x=sqrt(5/2),x=-sqrt(5/2)