What are the solutions to the equation completesquare 4x^2-x=0 ?

The solutions to the equation completesquare 4x^2-x=0 are x= 1/4 ,x=0

Find the zeros of completesquare 4x^2-x=0

The zeros of completesquare 4x^2-x=0 are x= 1/4 ,x=0

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4 x^{2} - x = 0

x = \frac{1}{4}, x = 0

Decimal Notation

x = 0.25, x = 0

Solution steps

4 x^{2} - x = 0

Divide both sides by

4

\frac{4 x ^{2} - x}{4} = \frac{0}{4}

x^{2} - \frac{x}{4} = 0

Rewrite in the form

(x + a)^{2} = b

(x - \frac{1}{8})^{2} = \frac{1}{64}

For

the solutions are

f (x) = a, - a

Solve

x - \frac{1}{8} = \frac{1}{64} : x = \frac{1}{4}

Solve

x - \frac{1}{8} = - \frac{1}{64} : x = 0

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = 0

A, A + BC = (A + B) (A + C)

x, s (x) = x^{2} - 4 x + 3

4. 5^{2} + 3. 5^{2} = c^{2}

x^{2} + (- 4) x + 2 = 0

- 5 x^{2} + 20 x - 25 = 0

What are the solutions to the equation completesquare 4x^2-x=0 ?
The solutions to the equation completesquare 4x^2-x=0 are x= 1/4 ,x=0
Find the zeros of completesquare 4x^2-x=0
The zeros of completesquare 4x^2-x=0 are x= 1/4 ,x=0