What are the solutions to the equation k^2-4k-5=0 ?

The solutions to the equation k^2-4k-5=0 are k=5,k=-1

Find the zeros of k^2-4k-5=0

The zeros of k^2-4k-5=0 are k=5,k=-1

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k^{2} - 4 k - 5 = 0

k = 5, k = - 1

Solution steps

k^{2} - 4 k - 5 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 5) = 6

k_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 1}, k_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 1}

k = \frac{- ( - 4 ) + 6}{2 \cdot 1} : 5

k = \frac{- ( - 4 ) - 6}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

k = 5, k = - 1

2 x^{2} + 32 x + 256 = 0

5 x^{2} + 30 x + 15 = 0

y, 5 x^{3} - x y^{2} + 3 y = c

5 x^{2} - 8 x + 13 = 0

7 (x - 1) (x + 1) = 0

What are the solutions to the equation k^2-4k-5=0 ?
The solutions to the equation k^2-4k-5=0 are k=5,k=-1
Find the zeros of k^2-4k-5=0
The zeros of k^2-4k-5=0 are k=5,k=-1