What are the solutions to the equation 2x^2-5x-21=0 ?

The solutions to the equation 2x^2-5x-21=0 are x=(5+sqrt(193))/4 ,x=(5-sqrt(193))/4

Find the zeros of 2x^2-5x-21=0

The zeros of 2x^2-5x-21=0 are x=(5+sqrt(193))/4 ,x=(5-sqrt(193))/4

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2 x^{2} - 5 x - 21 = 0

x = \frac{5 + 193}{4}, x = \frac{5 - 193}{4}

Decimal Notation

x = 4.72311 \dots, x = - 2.22311 \dots

Solution steps

2 x^{2} - 5 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 21 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 21) = 193

x_{1, 2} = \frac{- ( - 5 ) \pm 193}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 193}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 193}{2 \cdot 2}

x = \frac{- ( - 5 ) + 193}{2 \cdot 2} : \frac{5 + 193}{4}

x = \frac{- ( - 5 ) - 193}{2 \cdot 2} : \frac{5 - 193}{4}

The solutions to the quadratic equation are:

x = \frac{5 + 193}{4}, x = \frac{5 - 193}{4}

x, x^{2} + 7 x - 2 = 0

x^{2} + 5 x - 6.25 = 43.75

x^{2} + 83 = - 20 x

x^{2} - 0.016 x - 0.064 = 0

x, x y - x^{2} + 3 = 0

What are the solutions to the equation 2x^2-5x-21=0 ?
The solutions to the equation 2x^2-5x-21=0 are x=(5+sqrt(193))/4 ,x=(5-sqrt(193))/4
Find the zeros of 2x^2-5x-21=0
The zeros of 2x^2-5x-21=0 are x=(5+sqrt(193))/4 ,x=(5-sqrt(193))/4