What are the solutions to the equation z^2-13z=-42 ?

The solutions to the equation z^2-13z=-42 are z=7,z=6

Find the zeros of z^2-13z=-42

The zeros of z^2-13z=-42 are z=7,z=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

z^{2} - 13 z = - 42

z = 7, z = 6

Solution steps

z^{2} - 13 z = - 42

Move

42

to the left side

z^{2} - 13 z + 42 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 42}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 42 = 1

z_{1, 2} = \frac{- ( - 13 ) \pm 1}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 13 ) + 1}{2 \cdot 1}, z_{2} = \frac{- ( - 13 ) - 1}{2 \cdot 1}

z = \frac{- ( - 13 ) + 1}{2 \cdot 1} : 7

z = \frac{- ( - 13 ) - 1}{2 \cdot 1} : 6

The solutions to the quadratic equation are:

z = 7, z = 6

s^{2} - 13 s + 36 = 0

x^{2} = - 11 x - 24

2 x^{2} + 4 x - 10

4905 x^{2} - 12 x - 70 = 0

3 x^{2} - 12 x - 5 = 0

What are the solutions to the equation z^2-13z=-42 ?
The solutions to the equation z^2-13z=-42 are z=7,z=6
Find the zeros of z^2-13z=-42
The zeros of z^2-13z=-42 are z=7,z=6