What are the solutions to the equation (x-8)(x-2)=-9 ?

The solutions to the equation (x-8)(x-2)=-9 are x=5

Find the zeros of (x-8)(x-2)=-9

The zeros of (x-8)(x-2)=-9 are x=5

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(x - 8) (x - 2) = - 9

x = 5

Solution steps

(x - 8) (x - 2) = - 9

Expand

(x - 8) (x - 2) : x^{2} - 10 x + 16

x^{2} - 10 x + 16 = - 9

Move

9

to the left side

x^{2} - 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 10 )}{2 \cdot 1}

\frac{- ( - 10 )}{2 \cdot 1} = 5

x = 5

The solution to the quadratic equation is:

x = 5

- 4 x^{2} + 2 x - 1 = x

3 x^{2} - 12 x - 4 = 0

x^{2} - 6 = 138

s^{2} + 3.91 s + 14.846 = 0

2 (x - 3)^{2} + 10 = 24

What are the solutions to the equation (x-8)(x-2)=-9 ?
The solutions to the equation (x-8)(x-2)=-9 are x=5
Find the zeros of (x-8)(x-2)=-9
The zeros of (x-8)(x-2)=-9 are x=5