What are the solutions to the equation x^2+6x+9=-3x+9 ?

The solutions to the equation x^2+6x+9=-3x+9 are x=0,x=-9

Find the zeros of x^2+6x+9=-3x+9

The zeros of x^2+6x+9=-3x+9 are x=0,x=-9

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x^{2} + 6 x + 9 = - 3 x + 9

x = 0, x = - 9

Solution steps

x^{2} + 6 x + 9 = - 3 x + 9

Move

9

to the left side

x^{2} + 6 x = - 3 x

Move

3 x

to the left side

x^{2} + 9 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 0 = 9

x_{1, 2} = \frac{- 9 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 9}{2 \cdot 1}, x_{2} = \frac{- 9 - 9}{2 \cdot 1}

x = \frac{- 9 + 9}{2 \cdot 1} : 0

x = \frac{- 9 - 9}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 0, x = - 9

(2 - x)^{2} + (2 - x) - 20 = 0

2 x (x + 4) = (x + 3) (x - 3)

z^{2} - 5 \cdot 25 = 1 0^{2}

(2 x + 3) = x (1 - 3 x)

(t + 4) (t + 7) = 0

What are the solutions to the equation x^2+6x+9=-3x+9 ?
The solutions to the equation x^2+6x+9=-3x+9 are x=0,x=-9
Find the zeros of x^2+6x+9=-3x+9
The zeros of x^2+6x+9=-3x+9 are x=0,x=-9