What are the solutions to the equation 9y^2-18y+9=0 ?

The solutions to the equation 9y^2-18y+9=0 are y=1

Find the zeros of 9y^2-18y+9=0

The zeros of 9y^2-18y+9=0 are y=1

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9 y^{2} - 18 y + 9 = 0

y = 1

Solution steps

9 y^{2} - 18 y + 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 9 \cdot 9}{2 \cdot 9}

(- 18)^{2} - 4 \cdot 9 \cdot 9 = 0

y_{1, 2} = \frac{- ( - 18 ) \pm 0}{2 \cdot 9}

y = \frac{- ( - 18 )}{2 \cdot 9}

\frac{- ( - 18 )}{2 \cdot 9} = 1

y = 1

The solution to the quadratic equation is:

y = 1

3 (x + 8)^{2} = 5

(x + 8) (x - 4) - 2 (x - 8) (x - 4) = 24 (x - 8)

(6 x - 7)^{2} + 12 (6 x - 7) + 36 = 0

x^{2} + 5 x - 14 = - 8

x^{2} + 6 x + 7 = - 2 x

What are the solutions to the equation 9y^2-18y+9=0 ?
The solutions to the equation 9y^2-18y+9=0 are y=1
Find the zeros of 9y^2-18y+9=0
The zeros of 9y^2-18y+9=0 are y=1