What are the solutions to the equation 84a^2+76a=280 ?

The solutions to the equation 84a^2+76a=280 are a= 10/7 ,a=-7/3

Find the zeros of 84a^2+76a=280

The zeros of 84a^2+76a=280 are a= 10/7 ,a=-7/3

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84 a^{2} + 76 a = 280

a = \frac{10}{7}, a = - \frac{7}{3}

Decimal Notation

a = 1.42857 \dots, a = - 2.33333 \dots

Solution steps

84 a^{2} + 76 a = 280

Move

280

to the left side

84 a^{2} + 76 a - 280 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 76 \pm 7 6 ^{2} - 4 \cdot 84 ( - 280 )}{2 \cdot 84}

7 6^{2} - 4 \cdot 84 (- 280) = 316

a_{1, 2} = \frac{- 76 \pm 316}{2 \cdot 84}

Separate the solutions

a_{1} = \frac{- 76 + 316}{2 \cdot 84}, a_{2} = \frac{- 76 - 316}{2 \cdot 84}

a = \frac{- 76 + 316}{2 \cdot 84} : \frac{10}{7}

a = \frac{- 76 - 316}{2 \cdot 84} : - \frac{7}{3}

The solutions to the quadratic equation are:

a = \frac{10}{7}, a = - \frac{7}{3}

y, x + (y - 6)^{2} = 0

- 4 = - x^{2}

(x - 6)^{2} = - 32

2 x^{2} - 12 x - 9

(x - 10)^{2} + x (x + 17) = 104

What are the solutions to the equation 84a^2+76a=280 ?
The solutions to the equation 84a^2+76a=280 are a= 10/7 ,a=-7/3
Find the zeros of 84a^2+76a=280
The zeros of 84a^2+76a=280 are a= 10/7 ,a=-7/3