What are the solutions to the equation x^2-14x+16=-8 ?

The solutions to the equation x^2-14x+16=-8 are x=12,x=2

Find the zeros of x^2-14x+16=-8

The zeros of x^2-14x+16=-8 are x=12,x=2

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x^{2} - 14 x + 16 = - 8

x = 12, x = 2

Solution steps

x^{2} - 14 x + 16 = - 8

Move

8

to the left side

x^{2} - 14 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 24 = 10

x_{1, 2} = \frac{- ( - 14 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 10}{2 \cdot 1}

x = \frac{- ( - 14 ) + 10}{2 \cdot 1} : 12

x = \frac{- ( - 14 ) - 10}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 12, x = 2

x^{2} + 6 x = - 25

2 x^{2} - 17 x + 36 = 0

x^{2} = 4^{2} + 7^{2}

x, (1 + x)^{2} y = k^{2}

32 = x^{2}

What are the solutions to the equation x^2-14x+16=-8 ?
The solutions to the equation x^2-14x+16=-8 are x=12,x=2
Find the zeros of x^2-14x+16=-8
The zeros of x^2-14x+16=-8 are x=12,x=2