What are the solutions to the equation -2x^2-13x=0 ?

The solutions to the equation -2x^2-13x=0 are x=-13/2 ,x=0

Find the zeros of -2x^2-13x=0

The zeros of -2x^2-13x=0 are x=-13/2 ,x=0

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- 2 x^{2} - 13 x = 0

x = - \frac{13}{2}, x = 0

Decimal Notation

x = - 6.5, x = 0

Solution steps

- 2 x^{2} - 13 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

(- 13)^{2} - 4 (- 2) \cdot 0 = 13

x_{1, 2} = \frac{- ( - 13 ) \pm 13}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 13}{2 ( - 2 )}, x_{2} = \frac{- ( - 13 ) - 13}{2 ( - 2 )}

x = \frac{- ( - 13 ) + 13}{2 ( - 2 )} : - \frac{13}{2}

x = \frac{- ( - 13 ) - 13}{2 ( - 2 )} : 0

The solutions to the quadratic equation are:

x = - \frac{13}{2}, x = 0

\frac{1}{4} + y^{2} = 1

y, x^{3} + x y - y^{2} = 0

7 r^{2} - 16 k + 3 = 3

- 24 = - 5 b - b^{2}

x, x^{2} = y^{4}

What are the solutions to the equation -2x^2-13x=0 ?
The solutions to the equation -2x^2-13x=0 are x=-13/2 ,x=0
Find the zeros of -2x^2-13x=0
The zeros of -2x^2-13x=0 are x=-13/2 ,x=0