What are the solutions to the equation 5=x^2+1 ?

The solutions to the equation 5=x^2+1 are x=2,x=-2

Find the zeros of 5=x^2+1

The zeros of 5=x^2+1 are x=2,x=-2

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5 = x^{2} + 1

x = 2, x = - 2

Solution steps

5 = x^{2} + 1

Switch sides

x^{2} + 1 = 5

Move

1

to the right side

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

7 r^{2} - 14 r = - 7

(2 x + 3) (x + 4) = 228

3 (4 x^{2} - 1) + 6 (- 2 x + 3) = - 7

5 x^{2} - 2 x - 35 = 0

4 n^{2} - 20 n + 16 = 0

What are the solutions to the equation 5=x^2+1 ?
The solutions to the equation 5=x^2+1 are x=2,x=-2
Find the zeros of 5=x^2+1
The zeros of 5=x^2+1 are x=2,x=-2