What are the solutions to the equation y^2-5y=14 ?

The solutions to the equation y^2-5y=14 are y=7,y=-2

Find the zeros of y^2-5y=14

The zeros of y^2-5y=14 are y=7,y=-2

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y^{2} - 5 y = 14

y = 7, y = - 2

Solution steps

y^{2} - 5 y = 14

Move

14

to the left side

y^{2} - 5 y - 14 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 14) = 9

y_{1, 2} = \frac{- ( - 5 ) \pm 9}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 5 ) + 9}{2 \cdot 1}, y_{2} = \frac{- ( - 5 ) - 9}{2 \cdot 1}

y = \frac{- ( - 5 ) + 9}{2 \cdot 1} : 7

y = \frac{- ( - 5 ) - 9}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

y = 7, y = - 2

2 x^{2} + 128 x - 4096 = 0

4 (7 - 7 x^{2}) = 7

2 x^{2} + x - 3 = 0

x (x - 7) = 2 x

x (x - c) = a

What are the solutions to the equation y^2-5y=14 ?
The solutions to the equation y^2-5y=14 are y=7,y=-2
Find the zeros of y^2-5y=14
The zeros of y^2-5y=14 are y=7,y=-2