What are the solutions to the equation 0.02x^2-0.3x=20 ?

The solutions to the equation 0.02x^2-0.3x=20 are x=40,x=-25

Find the zeros of 0.02x^2-0.3x=20

The zeros of 0.02x^2-0.3x=20 are x=40,x=-25

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0.02 x^{2} - 0.3 x = 20

x = 40, x = - 25

Solution steps

0.02 x^{2} - 0.3 x = 20

Multiply both sides by

100

2 x^{2} - 30 x = 2000

Move

2000

to the left side

2 x^{2} - 30 x - 2000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 2 ( - 2000 )}{2 \cdot 2}

(- 30)^{2} - 4 \cdot 2 (- 2000) = 130

x_{1, 2} = \frac{- ( - 30 ) \pm 130}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 30 ) + 130}{2 \cdot 2}, x_{2} = \frac{- ( - 30 ) - 130}{2 \cdot 2}

x = \frac{- ( - 30 ) + 130}{2 \cdot 2} : 40

x = \frac{- ( - 30 ) - 130}{2 \cdot 2} : - 25

The solutions to the quadratic equation are:

x = 40, x = - 25

4 x^{2} + 10 x - 4 = 0

(x + 5) 2 + 6 = 2 (x + 4) (x + 2)

16 x^{2} = 11

4 x^{2} - 8 x + 7

4 x^{2} - 8 x + 2

What are the solutions to the equation 0.02x^2-0.3x=20 ?
The solutions to the equation 0.02x^2-0.3x=20 are x=40,x=-25
Find the zeros of 0.02x^2-0.3x=20
The zeros of 0.02x^2-0.3x=20 are x=40,x=-25