What are the solutions to the equation x^2-21x-5=0 ?

The solutions to the equation x^2-21x-5=0 are x=(21+sqrt(461))/2 ,x=(21-sqrt(461))/2

Find the zeros of x^2-21x-5=0

The zeros of x^2-21x-5=0 are x=(21+sqrt(461))/2 ,x=(21-sqrt(461))/2

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x^{2} - 21 x - 5 = 0

x = \frac{21 + 461}{2}, x = \frac{21 - 461}{2}

Decimal Notation

x = 21.23545 \dots, x = - 0.23545 \dots

Solution steps

x^{2} - 21 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 21)^{2} - 4 \cdot 1 \cdot (- 5) = 461

x_{1, 2} = \frac{- ( - 21 ) \pm 461}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 21 ) + 461}{2 \cdot 1}, x_{2} = \frac{- ( - 21 ) - 461}{2 \cdot 1}

x = \frac{- ( - 21 ) + 461}{2 \cdot 1} : \frac{21 + 461}{2}

x = \frac{- ( - 21 ) - 461}{2 \cdot 1} : \frac{21 - 461}{2}

The solutions to the quadratic equation are:

x = \frac{21 + 461}{2}, x = \frac{21 - 461}{2}

3 x + 18 = x^{2}

(6 - x)^{2} = 64

x, f (x + 3) = 3 x^{2} + 3 x - 3

(2 - x) (x + 1) - x (x - 1) = 2

18 = (- 6 + 3)^{2} + (2 - y)^{2}

What are the solutions to the equation x^2-21x-5=0 ?
The solutions to the equation x^2-21x-5=0 are x=(21+sqrt(461))/2 ,x=(21-sqrt(461))/2
Find the zeros of x^2-21x-5=0
The zeros of x^2-21x-5=0 are x=(21+sqrt(461))/2 ,x=(21-sqrt(461))/2