What are the solutions to the equation x^2+20x-200=0 ?

The solutions to the equation x^2+20x-200=0 are x=10(sqrt(3)-1),x=-10(1+sqrt(3))

Find the zeros of x^2+20x-200=0

The zeros of x^2+20x-200=0 are x=10(sqrt(3)-1),x=-10(1+sqrt(3))

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x^{2} + 20 x - 200 = 0

x = 10 (3 - 1), x = - 10 (1 + 3)

Solution steps

x^{2} + 20 x - 200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot ( - 200 )}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot (- 200) = 203

x_{1, 2} = \frac{- 20 \pm 20 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 20 3}{2 \cdot 1}, x_{2} = \frac{- 20 - 20 3}{2 \cdot 1}

x = \frac{- 20 + 20 3}{2 \cdot 1} : 10 (3 - 1)

x = \frac{- 20 - 20 3}{2 \cdot 1} : - 10 (1 + 3)

The solutions to the quadratic equation are:

x = 10 (3 - 1), x = - 10 (1 + 3)

3 x^{2} - 2 x - 1 = 0

5 x^{2} + 4 x = 3

5 x^{2} + 4 x = 4

1 x^{2} + b x + c = 0

x^{2} + x + 13 = 4 + 7 x

What are the solutions to the equation x^2+20x-200=0 ?
The solutions to the equation x^2+20x-200=0 are x=10(sqrt(3)-1),x=-10(1+sqrt(3))
Find the zeros of x^2+20x-200=0
The zeros of x^2+20x-200=0 are x=10(sqrt(3)-1),x=-10(1+sqrt(3))