What are the solutions to the equation 18x-3x^2=27 ?

The solutions to the equation 18x-3x^2=27 are x=3

Find the zeros of 18x-3x^2=27

The zeros of 18x-3x^2=27 are x=3

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18 x - 3 x^{2} = 27

x = 3

Solution steps

18 x - 3 x^{2} = 27

Move

27

to the left side

18 x - 3 x^{2} - 27 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 x^{2} + 18 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 ( - 3 ) ( - 27 )}{2 ( - 3 )}

1 8^{2} - 4 (- 3) (- 27) = 0

x_{1, 2} = \frac{- 18 \pm 0}{2 ( - 3 )}

x = \frac{- 18}{2 ( - 3 )}

\frac{- 18}{2 ( - 3 )} = 3

x = 3

The solution to the quadratic equation is:

x = 3

(x - 4)^{3} - (x - 3)^{3} = 343

(x + 2)^{2} = x + 2

(\frac{9}{41})^{2} + y^{2} = 1

1 6^{2} = x^{2} + 6^{2}

13 x^{2} - 3 x = 4 x^{2} + 21

What are the solutions to the equation 18x-3x^2=27 ?
The solutions to the equation 18x-3x^2=27 are x=3
Find the zeros of 18x-3x^2=27
The zeros of 18x-3x^2=27 are x=3