What are the solutions to the equation 4x^2-1=3 ?

The solutions to the equation 4x^2-1=3 are x=1,x=-1

Find the zeros of 4x^2-1=3

The zeros of 4x^2-1=3 are x=1,x=-1

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4 x^{2} - 1 = 3

x = 1, x = - 1

Solution steps

4 x^{2} - 1 = 3

Move

1

to the right side

4 x^{2} = 4

Divide both sides by

4

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

(y + 1)^{2} - 9 = 0

x^{2} - 12 x - 26 = 0

x^{2} - 1 = lo g_{3} (27)

4 x^{2} + 18 x + 18 = 0

x^{2} + 18 x + 81 = 49

What are the solutions to the equation 4x^2-1=3 ?
The solutions to the equation 4x^2-1=3 are x=1,x=-1
Find the zeros of 4x^2-1=3
The zeros of 4x^2-1=3 are x=1,x=-1