What are the solutions to the equation solvefor x,y=x^2-20x ?

The solutions to the equation solvefor x,y=x^2-20x are x=10+sqrt(y+100),x=10-sqrt(y+100)

Find the zeros of solvefor x,y=x^2-20x

The zeros of solvefor x,y=x^2-20x are x=10+sqrt(y+100),x=10-sqrt(y+100)

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solve for

x, y = x^{2} - 20 x

x = 10 + y + 100, x = 10 - y + 100

Solution steps

y = x^{2} - 20 x

Switch sides

x^{2} - 20 x = y

Move

y

to the left side

x^{2} - 20 x - y = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot ( - y )}{2 \cdot 1}

Simplify

(- 20)^{2} - 4 \cdot 1 \cdot (- y) : 2 100 + y

x_{1, 2} = \frac{- ( - 20 ) \pm 2 100 + y}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 2 100 + y}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 2 100 + y}{2 \cdot 1}

x = \frac{- ( - 20 ) + 2 100 + y}{2 \cdot 1} : 10 + y + 100

x = \frac{- ( - 20 ) - 2 100 + y}{2 \cdot 1} : 10 - y + 100

The solutions to the quadratic equation are:

x = 10 + y + 100, x = 10 - y + 100

3 x^{2} + 14 x - 1 = 7 x - 3

3 x^{2} + 10 x + 20 = 10 - 3 x

x, f (x + 2) = 4 x^{2} + 3

2 x^{2} - 10 x + 10 = 0

x - 3 = x^{2}

What are the solutions to the equation solvefor x,y=x^2-20x ?
The solutions to the equation solvefor x,y=x^2-20x are x=10+sqrt(y+100),x=10-sqrt(y+100)
Find the zeros of solvefor x,y=x^2-20x
The zeros of solvefor x,y=x^2-20x are x=10+sqrt(y+100),x=10-sqrt(y+100)