What are the solutions to the equation quadraticformula 2x^2+7x+6=0 ?

The solutions to the equation quadraticformula 2x^2+7x+6=0 are x=-3/2 ,x=-2

Find the zeros of quadraticformula 2x^2+7x+6=0

The zeros of quadraticformula 2x^2+7x+6=0 are x=-3/2 ,x=-2

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2 x^{2} + 7 x + 6 = 0

x = - \frac{3}{2}, x = - 2

Decimal Notation

x = - 1.5, x = - 2

Solution steps

2 x^{2} + 7 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

7^{2} - 4 \cdot 2 \cdot 6 = 1

x_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 1}{2 \cdot 2}, x_{2} = \frac{- 7 - 1}{2 \cdot 2}

x = \frac{- 7 + 1}{2 \cdot 2} : - \frac{3}{2}

x = \frac{- 7 - 1}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = - 2

x^{2} + 3 x + 30 = 0

(x - 7) (5 x + 8) = 0

- \frac{1}{500} (x - 100)^{2} + 20 = 0

2 x^{2} + 2 x + 11

u, p = \frac{u ^{2}}{r}

What are the solutions to the equation quadraticformula 2x^2+7x+6=0 ?
The solutions to the equation quadraticformula 2x^2+7x+6=0 are x=-3/2 ,x=-2
Find the zeros of quadraticformula 2x^2+7x+6=0
The zeros of quadraticformula 2x^2+7x+6=0 are x=-3/2 ,x=-2