What are the solutions to the equation x^2+103=-18x+13 ?

The solutions to the equation x^2+103=-18x+13 are x=-9+3i,x=-9-3i

Find the zeros of x^2+103=-18x+13

The zeros of x^2+103=-18x+13 are x=-9+3i,x=-9-3i

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x^{2} + 103 = - 18 x + 13

x = - 9 + 3 i, x = - 9 - 3 i

Solution steps

x^{2} + 103 = - 18 x + 13

Move

13

to the left side

x^{2} + 90 = - 18 x

Move

18 x

to the left side

x^{2} + 90 + 18 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 18 x + 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 90}{2 \cdot 1}

Simplify

1 8^{2} - 4 \cdot 1 \cdot 90 : 6 i

x_{1, 2} = \frac{- 18 \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 6 i}{2 \cdot 1}, x_{2} = \frac{- 18 - 6 i}{2 \cdot 1}

x = \frac{- 18 + 6 i}{2 \cdot 1} : - 9 + 3 i

x = \frac{- 18 - 6 i}{2 \cdot 1} : - 9 - 3 i

The solutions to the quadratic equation are:

x = - 9 + 3 i, x = - 9 - 3 i

(2 b^{2} + 8 b) - 19 = 5

x^{2} = 4 b

- 2 x^{2} - 4 x + 0

3 x^{2} - 32 = 0

- 53 = 1 - 6 n^{2}

What are the solutions to the equation x^2+103=-18x+13 ?
The solutions to the equation x^2+103=-18x+13 are x=-9+3i,x=-9-3i
Find the zeros of x^2+103=-18x+13
The zeros of x^2+103=-18x+13 are x=-9+3i,x=-9-3i