What are the solutions to the equation -11+6x^2-4x^2=0 ?

The solutions to the equation -11+6x^2-4x^2=0 are x=sqrt(11/2),x=-sqrt(11/2)

Find the zeros of -11+6x^2-4x^2=0

The zeros of -11+6x^2-4x^2=0 are x=sqrt(11/2),x=-sqrt(11/2)

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- 11 + 6 x^{2} - 4 x^{2} = 0

x = \frac{11}{2}, x = - \frac{11}{2}

Solution steps

- 11 + 6 x^{2} - 4 x^{2} = 0

Move

11

to the right side

6 x^{2} - 4 x^{2} = 11

Add similar elements:

6 x^{2} - 4 x^{2} = 2 x^{2}

2 x^{2} = 11

Divide both sides by

2

x^{2} = \frac{11}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{11}{2}, x = - \frac{11}{2}

- x^{2} + 6 x + 2

12 = x^{2} - x

a, p (a - 4) = (a - 4)^{2} - 5

x, x^{2} + 8 x + 1 = 0

6 x = 2 x^{2} + 3

What are the solutions to the equation -11+6x^2-4x^2=0 ?
The solutions to the equation -11+6x^2-4x^2=0 are x=sqrt(11/2),x=-sqrt(11/2)
Find the zeros of -11+6x^2-4x^2=0
The zeros of -11+6x^2-4x^2=0 are x=sqrt(11/2),x=-sqrt(11/2)