What are the solutions to the equation 5w^2+13w=-15 ?

The solutions to the equation 5w^2+13w=-15 are w=-13/10+i(sqrt(131))/(10),w=-13/10-i(sqrt(131))/(10)

Find the zeros of 5w^2+13w=-15

The zeros of 5w^2+13w=-15 are w=-13/10+i(sqrt(131))/(10),w=-13/10-i(sqrt(131))/(10)

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5 w^{2} + 13 w = - 15

w = - \frac{13}{10} + i \frac{131}{10}, w = - \frac{13}{10} - i \frac{131}{10}

Solution steps

5 w^{2} + 13 w = - 15

Move

15

to the left side

5 w^{2} + 13 w + 15 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 5 \cdot 15}{2 \cdot 5}

Simplify

1 3^{2} - 4 \cdot 5 \cdot 15 : 131 i

w_{1, 2} = \frac{- 13 \pm 131 i}{2 \cdot 5}

Separate the solutions

w_{1} = \frac{- 13 + 131 i}{2 \cdot 5}, w_{2} = \frac{- 13 - 131 i}{2 \cdot 5}

w = \frac{- 13 + 131 i}{2 \cdot 5} : - \frac{13}{10} + i \frac{131}{10}

w = \frac{- 13 - 131 i}{2 \cdot 5} : - \frac{13}{10} - i \frac{131}{10}

The solutions to the quadratic equation are:

w = - \frac{13}{10} + i \frac{131}{10}, w = - \frac{13}{10} - i \frac{131}{10}

x (5 x - 29) = 42

- 8 x^{2} + 13 = - 1139

11 x^{2} + 30 x - 1 = 0

6 x^{2} - 96 x + 438 = 0

(x - 3)^{2} = - 27

What are the solutions to the equation 5w^2+13w=-15 ?
The solutions to the equation 5w^2+13w=-15 are w=-13/10+i(sqrt(131))/(10),w=-13/10-i(sqrt(131))/(10)
Find the zeros of 5w^2+13w=-15
The zeros of 5w^2+13w=-15 are w=-13/10+i(sqrt(131))/(10),w=-13/10-i(sqrt(131))/(10)